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Edexcel IGCSE·Maths·Edexcel IGCSE Maths

Angles, Polygons & Geometric Reasoning

5 min read

Angle facts, parallel lines, polygon angles, bearings and geometric reasoning.

Angle Facts You Must Know

Geometry questions reward clear reasoning, not just the right number. Every mark in an "angle chase" comes from a correct value and a correct reason. Start from the basic facts and quote them by name.

    Angles on a straight line add up to 180°180°180°.
    Angles around a point add up to 360°360°360°.
    Vertically opposite angles (formed when two straight lines cross) are equal.

Key terms

Vertically opposite — the pair of equal angles directly across an X-shaped crossing.

Transversal — a straight line that cuts across two (usually parallel) lines.

Interior angle — an angle inside a polygon at a vertex.

Exterior angle — the angle between a side and the extension of the next side.

Angles in Parallel Lines

When a transversal crosses parallel lines, three named pairs appear. Parallel lines are marked with matching arrowheads.

    Corresponding angles are equal — same position at each crossing (an "F-shape").
    Alternate angles are equal — opposite sides of the transversal, between the parallels (a "Z-shape").
    Co-interior angles add up to 180°180°180° — same side of the transversal, between the parallels (a "C-shape"). Also called allied angles.
a b parallel parallel a and b are alternate angles, so a = b
A transversal crossing two parallel lines, showing alternate, corresponding and co-interior angles

Watch out

Don't guess which rule applies from the look of the diagram. Trace the F, Z or C shape with your finger first, then name the rule. Co-interior is the only pair that sums to 180°180°180° — the other two are equal.

Triangles and Quadrilaterals

Angle properties you can quote as reasons:

    Angles in a triangle sum to 180°180°180°.
    Angles in a quadrilateral sum to 360°360°360°.
    An isosceles triangle has two equal sides and two equal base angles.
    An equilateral triangle has all angles 60°60°60°.
    The exterior angle of a triangle equals the sum of the two opposite interior angles.
QuadrilateralKey angle property
Square / RectangleAll angles 90°90°90°
ParallelogramOpposite angles equal; co-interior pairs sum to 180°180°180°
RhombusOpposite angles equal; diagonals bisect angles
TrapeziumOne pair of parallel sides; co-interior angles sum to 180°180°180°
KiteOne pair of opposite angles equal

Polygons: Interior and Exterior Angles

A polygon has nnn sides. Splitting it into triangles from one vertex gives (n−2)(n-2)(n−2) triangles, so:

Sum of interior angles=(n−2)×180°\text{Sum of interior angles} = (n-2)\times 180°Sum of interior angles=(n−2)×180°

The exterior angles of any polygon always sum to 360°360°360°, no matter how many sides.

At each vertex the interior and exterior angles lie on a straight line, so:

interior angle+exterior angle=180°\text{interior angle} + \text{exterior angle} = 180°interior angle+exterior angle=180°

interior ext pentagon n = 5
A pentagon showing one interior angle and its exterior angle

Regular Polygons

A regular polygon has all sides and all angles equal. Because the nnn exterior angles are equal and sum to 360°360°360°:

Exterior angle=360°nInterior angle=180°−360°n\text{Exterior angle} = \frac{360°}{n} \qquad \text{Interior angle} = 180° - \frac{360°}{n}Exterior angle=n360°​Interior angle=180°−n360°​

Exam tip

For regular polygons, work with the exterior angle first — it is just 360°÷n360° \div n360°÷n. To find nnn from an interior angle, find the exterior angle (180°−180° -180°− interior) and divide it into 360°360°360°. This is faster and less error-prone than the (n−2)×180°(n-2)\times180°(n−2)×180° formula.

Worked example

The interior angle of a regular polygon is 156°156°156°. How many sides does it have?

Exterior angle =180°−156°=24°= 180° - 156° = 24°=180°−156°=24°.

n=360°24°=15n = \dfrac{360°}{24°} = 15n=24°360°​=15 sides.

Worked example

Find the sum of the interior angles of a regular octagon, and the size of each interior angle.

Sum =(n−2)×180°=(8−2)×180°=6×180°=1080°= (n-2)\times 180° = (8-2)\times 180° = 6 \times 180° = 1080°=(n−2)×180°=(8−2)×180°=6×180°=1080°.

Each interior angle =1080°8=135°= \dfrac{1080°}{8} = 135°=81080°​=135°.

Check: exterior angle =360°÷8=45°= 360° \div 8 = 45°=360°÷8=45°, and 180°−45°=135°180° - 45° = 135°180°−45°=135°. ✓

Bearings

A bearing describes a direction as an angle measured:

  1. from North,
  2. clockwise,
  3. written with three figures (e.g. 072°072°072°, 135°135°135°, 310°310°310°).
N A B 063°
The bearing of B from A, measured clockwise from North

Worked example

The bearing of B from A is 063°063°063°. Find the bearing of A from B (the back bearing).

A back bearing differs by 180°180°180°. Since 063°<180°063° < 180°063°<180°, add:

063°+180°=243°063° + 180° = 243°063°+180°=243°.

So the bearing of A from B is 243°243°243°.

The North lines at A and B are parallel, so the rule is just co-interior / alternate angle reasoning in disguise: if the bearing is under 180°180°180°, add 180°180°180°; if it is 180°180°180° or more, subtract 180°180°180°.

Writing Geometric Reasons in Proofs

Higher tier "prove that" and "give a reason" questions expect the exact wording. Each step is value + reason.

Use this reasonWhen
angles on a straight line sum to 180°180°180°two/three angles make a line
angles around a point sum to 360°360°360°angles fill a full turn
vertically opposite angles are equaltwo lines cross
alternate angles are equalZ-shape in parallel lines
corresponding angles are equalF-shape in parallel lines
co-interior angles sum to 180°180°180°C-shape in parallel lines
angles in a triangle sum to 180°180°180°inside a triangle
base angles of an isosceles triangle are equaltwo equal sides

Exam tip

Never write a reason as "obvious" or "they look the same". Write the named fact in full. A correct angle with a missing or wrong reason usually scores only half the marks. Set work out line by line, quoting one fact per line.

Worked example

In the diagram, ABABAB is parallel to CDCDCD. A transversal makes an angle of 58°58°58° with ABABAB. Find the co-interior angle xxx on CDCDCD, giving a reason.

x=180°−58°=122°x = 180° - 58° = 122°x=180°−58°=122° (co-interior angles sum to 180°180°180°).

Quick Recap

    Line =180°=180°=180°, point =360°=360°=360°, vertically opposite are equal.
    Parallel lines: alternate and corresponding equal; co-interior sum to 180°180°180°.
    Polygon interior sum =(n−2)×180°=(n-2)\times180°=(n−2)×180°; exterior sum =360°=360°=360° always.
    Regular: exterior =360°/n=360°/n=360°/n, interior =180°−360°/n=180°-360°/n=180°−360°/n.
    Bearings: from North, clockwise, three figures; back bearing ±180°\pm180°±180°.
    Always pair every value with its named reason.

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