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Edexcel IGCSE·Chemistry·IGCSE Chemistry

The Mole & Calculations

14 min read

Relative formula mass, the mole, reacting masses, concentrations and gas volumes.

Chemical calculations use the mole to connect masses, volumes and numbers of particles.

Relative formula mass and the mole

n=mMrn=c×Vn=Vgas24 (dm3 at rtp)n = \frac{m}{M_r} \qquad n = c \times V \qquad n = \frac{V_\text{gas}}{24}\ (\text{dm}^3\text{ at rtp})n=Mr​m​n=c×Vn=24Vgas​​ (dm3 at rtp)

Worked example. How many moles in 505050 g of CaCO₃? Mr=40+12+48=100M_r = 40 + 12 + 48 = 100Mr​=40+12+48=100, so n=50100=0.5n = \dfrac{50}{100} = 0.5n=10050​=0.5 mol.

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